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x^2-20x+100=8.6
We move all terms to the left:
x^2-20x+100-(8.6)=0
We add all the numbers together, and all the variables
x^2-20x+91.4=0
a = 1; b = -20; c = +91.4;
Δ = b2-4ac
Δ = -202-4·1·91.4
Δ = 34.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-\sqrt{34.4}}{2*1}=\frac{20-\sqrt{34.4}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+\sqrt{34.4}}{2*1}=\frac{20+\sqrt{34.4}}{2} $
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